contestada


30cm3 of NaOH is neutralised by 12.3cm3 of 0.2mol/l HCI. What is the concentration of the NaOH. 0.82 mol/l 0.082 mol/l 82 mol/l 0.49 mol/l
​

Respuesta :

Lets see

  • C1V1=C2V2
  • 30C1=0.2(12.3)
  • 30C1=2.46
  • C1=2.46/30
  • C1=0.082mol/L
SmaгtieGurL

Answer:

Step 1: Calculate the amount of sodium hydroxide in moles

  • Amount of solute in mol = concentration in mol/dm 3 × volume in dm 3

  • Amount of sodium hydroxide = 0.100 × 0.0250.= 0.00250 mol.

  • The balanced equation is: NaOH(aq) + HCl(aq) → NaCl(aq) + H 2O(l)

  • So the mole ratio NaOH:HCl is 1:1.

Otras preguntas