Answer:
See below
Step-by-step explanation:
[tex]\csc\theta=1.2711\\\\\frac{1}{\csc\theta}=\frac{1}{1.2711}\\ \\\sin\theta=\frac{1}{1.2711}\\ \\\theta=\sin^{-1}(\frac{1}{1.2711})\\\\\theta\approx51.88^\circ\approx52^\circ[/tex]
Remember the identity [tex]\csc\theta=\frac{1}{\sin\theta}[/tex], so [tex]\sin\theta=\frac{1}{\csc\theta}[/tex] and it makes the problem easier. Just remember to take the inverse sine (let me know if you are not sure what that means).
