The triangle PAT is an isosceles triangle because the side lengths PA and AT are congruent
How to prove that the triangle is an isosceles triangle?
The points are given as:
P = (1,6)
A = (4,5)
T = (5,2)
Calculate the distance between both points as follows:
[tex]d = \sqrt{(x_2 -x_1)^2 + (y_2 -y_1)^2}[/tex]
So, we have:
[tex]PA = \sqrt{(1 -4)^2 + (6-5)^2}[/tex]
[tex]PA = \sqrt{10}[/tex]
[tex]PT = \sqrt{(1 -5)^2 + (6-2)^2}[/tex]
[tex]PT = \sqrt{32}[/tex]
[tex]AT = \sqrt{(4 -5)^2 + (5-2)^2}[/tex]
[tex]AT = \sqrt{10}[/tex]
Because the side lengths PA and AT are congruent, i.e. √10, then the triangle is an isosceles triangle
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