Right triangles and trigonometry

Answer:
x=5.11
Step-by-step explanation:
Hi there!
We are given a right triangle (notice the right angle), with one of the angles being equal to 64 degrees
We also know one of the sides is 42, another is x, and the other one is not marked
We want to find the value of x, which we can do using trigonometry
The 3 main trigonometric functions are:
Sine, which is opposite/hypotenuse
Cosine, which is adjacent/hypotenuse
Tangent, which is opposite/adjacent
First, let's find which side is which
The side opposite the 64 degree angle is the opposite; this side is the side marked as 42
The adjacent side would be the other leg (one of the sides creating the right angle); in this case, that would be the side marked as x
The hypotenuse in this case would be the side that hasn't been marked yet
Since we are given values for both the opposite and the adjacent, let's use tangent to find x
Since 64° was the angle we referenced to determine which side was which, we will also make the ratio with this angle.
Therefore, the ratio will be:
[tex]tan(64)=\frac{42}{x}[/tex]
Now we need to solve for x; start by multiplying both sides by x
x * tan(64) = 12
Now divide both sides by tan(64)
x = [tex]\frac{12}{tan(64)}[/tex]
Plug [tex]\frac{12}{tan(64)}[/tex] into your calculator; make sure the calculator is on degree, not radian mode
[tex]\frac{12}{tan(64)}[/tex] ≈ 5.11 (rounded to the nearest hundreth)
So x is about 5.11
Hope this helps!
Topic: trigonometry in right triangles
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