The quantity of pure antifreeze that must be added to 2 quarts of a 20% antifreeze solution to obtain a 60% antifreeze solution 2 quarts
How to solve equation?
- x = quarts of 100% antifreeze
You have 2 quarts of 20% antifreeze.
(100%)x + (20%)2 = 60%(x + 2)
100x + 40 = 60(x + 2)
100x + 40 = 60x + 120
100x - 60x = 120 - 40
40x = 80
x = 80/40
x = 2 quarts
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