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The number of children and adults who bought the tickets at the circus was 500 and 900 respectively.
How to write and solve equation?
let
- x = number of children
- y = number of adults
x + y = 1400
22x + 46y = 52,400
From equation (1)
x = 1400 - y
Substitute into (2)
22(1400 - y) + 46y = 52,400
30,800 - 22y + 46y = 52,400
- 22y + 46y = 52,400 - 30,800
24y = 21,600
y = 21,600 / 24
y = 900
substitute y into
x + y = 1400
x + 900 = 1400
x = 1400 - 900
x = 500
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The number of children's ticket that was bought is 500.
The number of adult's ticket that was bought is 900.
What is the linear equation that represents the question?
a + b = 1400 equation 1
22a + 46b = 52,400 equation 2
Where:
- a - number of children's ticket
- b = number of adult's ticket
What is the number of adult's ticket?
Multiply equation 1 by 22
22a + 22b = 30800 equation 3
Subtract equation 3 from equation 2
21,600 = 24b
b = 21,600 / 24
b = 900
What is the number of children's ticket?
Subtract 900 from 1400
1400 - 900 = 500
To learn more about simultaneous equations, please check: https://brainly.com/question/25875552
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