The required equation of the line is 5y=x.
We are given to find the equation of the line passing through the points (0, 0) and (15, 3).
We know that
The equation of a line passing through two points (a, b) and (c, d) is given by
[tex]y-b=\frac{d-b}{c-a}(x-a)[/tex]
Therefore, the equation of the line passing through the points (0, 0) and (15, 3) is given by,
Thus, the required equation of the line is
[tex]y-0=\frac{3-0}{15-0}(x-0)\\y=\frac{3}{15}x\\ y=\frac{1}{5}x\\ 5y=x[/tex]
Thus the required equation of the line is 5y=x.
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