The correct procedure is:
Dissolving 45 g of NaOH in enough water to make up to 750 mL of solution
This is defined as the mole of solute per unit litre of solution. Mathematically, it can be expressed as:
Molarity = mole / Volume
Mole = Molarity x Volume
Mole of NaOH = 1.5 × 0.75
Mole of NaOH = 1.125 mole
Mass = mole × molar mass
Mass of NaOH = 1.125 × 40
Mass of NaOH = 45 g
Thus, to obtain 750 mL of 1.5 M NaOH solution, 45 g of NaOH will be dissolved in enough water to make up to 750 mL of solution
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