Since the polyhedron is about 78.5 m², the radius of the sphere is 2.5 m
Since the sum of the faces of the polyhefron equals the surface area of the sphere, we find its surface area.
The surface area of sphere is given by A = 4πr² where r = radius of sphere
Making r subject of the formula, we have
r = √(A/4π)
Given that he sum of all the faces of the polyhedron is about 78.5 square meters, this is equal to the surface area of the sphere.
So, A = 78.5 m²
Substituting this into the equation for r, we have
r = √(A/4π)
r = √(78.5 m²/4π)
r = √(19.625 m²/π)
= √(6.246 m²)
= 2.499 m
≅ 2.5 m
So, the radius of the sphere is 2.5 m
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