EASY QUESTION Miguel plots points A, B, and C in the coordinate plane.

A. Distance between A and B is: 5 units.
B. Triangle ABC is not an equilateral triangle because only two of its sides are equal.
An equilateral triangle has three sides that have the same length.
Given the vertices with their coordinate points as:
A (-3, 2)
B (-6, -2)
C (0, -2)
Use the distance formula, [tex]d =\sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}[/tex], to find AB, BC, and AC:
AB = √[(−6−(−3))² + (−2−2)²]
AB = √25
AB = 5 units
BC = √[(−6−0)² + (−2−(−2))²]
BC = √36
BC = 6 units
AC = √[(−3−0)² + (2−(−2))²]
AC = 25
AC = 5 units
Only two of the sides of the triangle, AB and AC, are equal. Therefore, it is not an equilateral triangle.
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