pls help me out with this question

Height be h
[tex]\\ \rm\Rrightarrow tan\Theta=\dfrac{Perpendicular}{Base}[/tex]
[tex]\\ \rm\Rrightarrow tan54=\dfrac{h}{60}[/tex]
[tex]\\ \rm\Rrightarrow h=60tan54[/tex]
[tex]\\ \rm\Rrightarrow h=82.6\approx 83m[/tex]
Answer:
83 m (nearest metre)
Step-by-step explanation:
This can be modeled as a right triangle, where the base is 60 m and the height is the height of the building.
Alternate Interior Angles Theorem (Z-angles)
If a line intersects a set of parallel lines in the same plane at two distinct points, the alternate interior angles that are formed are congruent.
Using the Alternate Interior Angles theorem, the angle between the ground and the dashed line (angle of elevation) is 54°.
Tan trigonometric ratio
[tex]\sf \tan(\theta)=\dfrac{O}{A}[/tex]
where:
Given:
Substituting the given values into the formula and solving for h:
[tex]\implies \sf \tan(54^{\circ})=\dfrac{h}{60}[/tex]
[tex]\implies \sf h=60 \tan(54^{\circ})[/tex]
[tex]\implies \sf h=82.58291523...[/tex]
[tex]\implies \sf h=83\:\:m\:(nearest\:metre)[/tex]