Answer:
[tex]x = \dfrac{-1\pm i\sqrt{19}}{10}[/tex]
Step-by-step explanation:
[tex]~~~~~~5x^2 +x +1 = 0\\\\\implies x = \dfrac{-1\pm\sqrt{1^2 -4 (5)(1)}}{2(5)}\\\\\implies x = \dfrac{-1 \pm \sqrt{-19}}{10}\\\\\implies x = \dfrac{-1\pm i\sqrt{19}}{10}[/tex]
