Using the uniform distribution, considering that the novel has 435 pages, the probability that the page is numbered something between 21 and 31 is:
[tex]p = \frac{10}{435}[/tex]
It is a distribution with two bounds, a and b, in which each outcome is equally as likely.
The probability of finding a value between c and d is:
[tex]P(c \leq X \leq d) = \frac{d - c}{b - a}[/tex]
Researching the problem on the internet, it is found that the novel has 435 pages, hence a = 0, b = 435, and the probability that the page is numbered something between 21 and 31 is given by:
[tex]P(21 \leq X \leq 31) = \frac{31 - 21}{435 - 0} = \frac{10}{435}[/tex]
More can be learned about the uniform distribution at https://brainly.com/question/13889040
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