The resulting pressure of the gas after decreasing the initial volume is 3 atm.
According to the Boyle's Law at constant temperature, pressure of the gas is inversely proportional to the volume of the gas:
P ∝[tex]\frac{1}{V}[/tex]
For the given question required equation is:
P₁V₁ = P₂V₂, where
P₁ = initial pressure = 1.5 atm
V₁ = initial volume = 2 L
P₂ = final pressure = ?
V₂ = final volume = 1 L
On putting all these values on the above equation, we get
P₁V₁ = P₂V₂
P₂ =[tex]\frac{1.5}{2X1}[/tex] = 3atm
Hence required pressure is 3 atm.
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