The maximum height the ball will reach 7.316 ft. This height is less than a standard soccer goal's height.
When an object is thrown at an angle from the horizontal direction, the object is said to be in projectile motion. The object which follows the projectile motion is called the projectile.
Maximum height reached is given by
H = u²sin²θ /2g
where, u = initial velocity, θ is the angle of projection and g is the gravitational acceleration.
Consider the soccer ball is kicked toward a goal at a speed of 35 mph and an angle of 25 ° from horizontal,
Given is the speed 35mph = 35 x 1609/3600 = 15.65 m/s, θ =25 ° and g = 9.81 m/s²
Substituting the values, we get
H = (15.65)² (sin25 °)² / 2 x 9.81
H = 2.23 m
in feet, H = 7.316 ft
Thus, the maximum height is 7.316 ft. This height is less than a standard soccer goal's height, which is 8 feet from the ground.
Learn more about projectile.
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