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H E L P M E P L I Z
In the following exercises, classify each equation as a conditional equation, an identity, or a contradiction and then state the solution.
23z+19=3(5z-9)+8z+46
15y+32=2(10y-7)-5y+46

Respuesta :

The 2 equations are classified as Identities because both sides remain the same for all values of z.

How to Classify Equations?

1) We are given the equation;

23z + 19 = 3(5z - 9) + 8z + 46

Let us try z = 0

23(0) + 19 = 3(5(0) - 9) + 8(0) + 46

19 = -27 + 46

19 = 19

Let us try z = 5;

23(5) + 19 = 3(5(5) - 9) + 8(5) + 46

134 = 48 + 40 + 46

134 = 134

Thus, this is an identity as both sides remaining the same for all values of z.

2) We are given the equation;

15y + 32 = 2(10y - 7) - 5y + 46

At y = 0, we have;

15(0) + 32 = 2(10(0) - 7) - 5(0) + 46

32 = -14 + 46

32 = 32

Let us try y = 2;

15(2) + 32 = 2(10(2) - 7) - 5(2) + 46

62 = 26 - 10 + 46

62 = 62

This is an identity as both sides remaining the same for all values of z.

Read more about Equations at; https://brainly.com/question/1214333

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