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Two socks are selected at random from a draw of loose socks- there are 4 green socks and 6 yellow socks


What is the probability that two of the socks will both be green if the socks are drawn without replacement

Respuesta :

Using the hypergeometric distribution, it is found that there is a 0.1333 = 13.33% probability that two of the socks will both be green if the socks are drawn without replacement.

What is the hypergeometric distribution formula?

The formula is:

[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}[/tex]

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

The parameters are:

  • x is the number of successes.
  • N is the size of the population.
  • n is the size of the sample.
  • k is the total number of desired outcomes.

In this problem, we have that the values of the parameters are:

N = 10, k = 4, n = 2.

The probability that both are green is P(X = 2), hence:

[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}[/tex]

[tex]P(X = 2) = h(2,10,2,4) = \frac{C_{4,2}C_{6,0}}{C_{10,2}} = 0.1333[/tex]

0.1333 = 13.33% probability that two of the socks will both be green if the socks are drawn without replacement.

More can be learned about the hypergeometric distribution at https://brainly.com/question/24826394

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