answer with detail explanation if possible

The work done on a body when it is moved is 125J
It states that the Work done in moving a body is equal to the change in kinetic energy of the body
Kinetic energy = 1/2 mv²
Given is a body of mass m = 6kg, moving distance d =25 m in time t=5s.
Final Velocity v = 25/5 = 5 m/s
The body is initially at rest, so, final velocity is zero. Then, change in kinetic energy will be
ΔK.E = K.Ef - K.Ei
ΔK.E = 1/2 x 6 x (5)² -0
ΔK.E =125J
According to work energy theorem, work done is
W = 125J
Thus, the work done on a body when it is moved is 125J.
Learn more about work energy theorem.
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