Answer:
C. y = 20
Step-by-step explanation:
Given system of equations:
[tex]\begin{cases}3y = 18x + 6\\y = 2x + 14\end{cases}[/tex]
Multiply the second equation by 3:
[tex]\implies (3)y=(3)2x+(3)14[/tex]
[tex]\implies 3y=6x+42[/tex]
Subtract this from the first equation to eliminate 3y:
[tex]\begin{array}{r l}3y & = 18x+6\\-\quad3y&=6x+42\\\cline{1-2}0&=12x-36\end{array}[/tex]
Solve the resulting equation for x:
[tex]\implies 12x-36=0[/tex]
[tex]\implies 12x=36[/tex]
[tex]\implies x=3[/tex]
Substitute the found value of x into the original second equation and solve for y:
[tex]\implies y=2(3)+14[/tex]
[tex]\implies y=6+14[/tex]
[tex]\implies y=20[/tex]
