The exponential form when [x²y³)^(¹/₃)]/[∛x²y] is simplified gives us; [x^(²/₃) * y]/[x^(²/₃) * y^(¹/₃)]
The power of a digit defines a base number raised to the exponent, where base number is the factor which is multiplied by itself while exponent denotes the number of times the same base number is multiplied.
We want to simplify the exponents; [x²y³)^(¹/₃)]/[∛x²y]
Using rule of exponents, we have;
[x^(²/₃) * y]/[x^(²/₃) * y^(¹/₃)]
Read more about Exponents at; https://brainly.com/question/12882204
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