The area of this trapezoid is A = 55
We know that the application formula for calculating the area of a trapezoid is given by:
[tex] \boxed{ \large \sf A = \dfrac{(b + b) \times h}{2} } \\ \\ [/tex]
⚘ Then, the resolution will be:
[tex]{ \large \sf A = \dfrac{(7 + 15) \times 5}{2} } [/tex]
[tex]{ \large \sf A= \dfrac {22 \times 5}{2} } [/tex]
[tex]{ \large \sf A= \dfrac {110}{2} } [/tex]
[tex]\pink{ \boxed{ \purple{ \boxed{ \large \sf A= 55 }}}} \\ \\ [/tex]
Therefore, the area of this trapezoid will be, A = 55
