The enthalpy of formation (ΔHf) of [tex]Br_2[/tex](g) at 1.00 atm and 298 K is 0 kJ/mol. Hence, option A is correct.
The standard enthalpy of formation is defined as the enthalpy change for creating one mole of a compound from elements in their standard states.
The enthalpy of formation (ΔHf) of [tex]Br_2[/tex] (g) at 1.00 atm and 298 K is 0 kJ/mol.
It is because the enthalpy of formation of the molecule is only 0 in its standard state and for bromine, the standard state at 298K is the liquid state.
Hence, option A is correct.
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