Need help checking my work for Trigonometry. Will mark brainist!

Answer:
1. 0.9925 (4 d.p.)
2. 17°
3. 67°
Step-by-step explanation:
Question 2
⇒ sin 83° = 0.9925461516...
⇒ sin 83° = 0.9925 (4 d.p.)
Question 3
[tex]\sf \implies \sin X=0.2923[/tex]
[tex]\sf \implies X=\sin^{-1}(0.2923)[/tex]
[tex]\implies \sf X=16.99570395...^{\circ}[/tex]
[tex]\implies \sf X=17^{\circ}\:\:(nearest\:degree)[/tex]
Question 4
Sine Ratio
[tex]\sf \sin(\theta)=\dfrac{O}{H}[/tex]
where:
From inspection of the triangle:
Substitute the values into the formula and solve for W:
[tex]\implies \sf \sin(W)=\dfrac{24}{26}[/tex]
[tex]\implies \sf W= \sin^{-1}\left(\dfrac{24}{26}\right)[/tex]
[tex]\implies \sf W=67.38013505...^{\circ}[/tex]
[tex]\implies \sf W=67^{\circ}\:\:(nearest\:degree)[/tex]