The length of the immersed part of the wood is 0.2m.
The density is the ratio of the mass and the volume of the object. It is denoted by ρ.
ρ = mass/Volume = m/V
Volume = Area of cross-section A x height h
Given is a piece of wood of mass 40g =0.04kg and uniform cross-sectional area A= 2cm² =2x10⁻⁴ m² floats upright in water.
The density of water ,ρ = 1000 kg/m³
The density related to length of part immersed is
1000 = 0.04/ (2x10⁻⁴ x h)
h = 0.2m
Thus, the length of the immersed part of the wood is 0.2m.
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