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A gas has a volume of 0.550 l at a temperature of -55.0 c. what will the volume be if the temperature is increased to 30.0 c and the pressure remains constant?

Respuesta :

Gay-Lussac's law: [tex]\frac{V1}{T1}[/tex]=[tex]\frac{V2}{T2}[/tex]

We need to convert temperature from Celsius to Kelvin

-55 C = 218 K

30 C = 303 K

V2 = V1*T2 / T1 = 0.550 *303 / 218 = 0.764 l

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