The distance around the perimeter would be 120 ft.
Perimeter is the distance around the edge of a shape.
The complete question is
A garden is designed in the shape of a rhombus formed from 4 identical 30°-60°-90° triangles. The shorter distance across the middle of the garden measures 30 feet.
A rhombus is shown. Lines are drawn from each point to the opposite point to form 4 right triangles. The other 2 angle measures are 30 and 60 degrees. The base length of each triangle is 15 feet.
What is the distance around the perimeter of the garden?
let AE is the half of the diagonal AC.
AC = 30 ft.
So, AE = ½ * 30
AE = 15 ft
Now, using trigonometry
sin 30 = 15/AD
0.5= 15/AD
AD= 30 ft
Hence, distance around the perimeter would be: AD+AD+AD+AD=
=30 ft + 30 ft + 30 ft + 30 ft
= 120 ft.
Learn more about this concept here:
https://brainly.com/question/16400817
#SPJ1
