The probability that the spinner lands on an even number or on the unshaded section is; 3/5
From the spinner attached, we see that the number of sections on the spinner is 5 sections.
Now, we can also see that;
Number of even numbers section = 2
Number of shaded sections = 1
Thus, probability that the spinner lands on an even number or on the unshaded section is;
P(even number or unshaded section) = (2 + 1)/5 = 3/5
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