4 neutrons that are produced along with the Zn and sm. The complete final equation is: ²³⁵U + ¹n → [tex]\;^{72}Zn+\;^{160}sm[/tex] + 4 n
Atomic mass, the quantity of matter contained in an atom of an element.
1) In the left side of the transmutation equation appears:
²³⁵U + ¹n →
Deleting the atomic number (subscript to the left) because the question does not show them as it is focused on a number of neutrons.
2) The right side of the transmutation equation has:
→ [tex]\;^{72}Zn+\;^{160}sm[/tex] +?
3) The total mass number of the left side is 235 + 1 = 236
4) The total mass number of Zn and sm on the right side is 160 + 72 = 232
5) Then, you are lacking 236 - 232 = 4 unit masses on the right side which are the 4 neutrons that are produced along with the Zn and sm.
The complete final equation is:
²³⁵U + ¹n → [tex]\;^{72}Zn+\;^{160}sm[/tex] + 4 n
Learn more about the atomic mass here:
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