Type the correct answer in each box.


Scale: 1 unit = 10 meters

The hyperbolic cross section of a cooling tower is given by the equation 4x2 − y2 + 16y − 80 = 0. The center of the cooling tower is the same as the center of the hyperbola, and the x-axis represents the ground surface.

The diameter at the center of the tower is
meters. The center of the tower is
meters above the ground.

Type the correct answer in each box Scale 1 unit 10 meters The hyperbolic cross section of a cooling tower is given by the equation 4x2 y2 16y 80 0 The center o class=

Respuesta :

The diameter at the centre of the tower is 4 meters and the centre of the tower is 8 meters above the ground.

What is hyperbola?

It's a two-dimensional geometry curve with two components that are both symmetric. In other words, the number of points in two-dimensional geometry that have a constant difference between them and two fixed points in the plane can be defined.

We have an equation of the hyperbola:

4x² − y² + 16y − 80 = 0

4x² − y² + 16y + 64 - 64 − 80 = 0

4x² - (y - 8)² = 16

[tex]\rm \dfrac{4x^2}{16} - \dfrac{(y-8)^2}{16} = 1[/tex]

[tex]\rm \dfrac{x^2}{2^2} - \dfrac{(y-8)^2}{8^2} = 1[/tex]

The above equation represents the standard form of the hyperbola.

a = 2

b = 4

The diameter at the centre of the tower = 2a = 2(2) = 4 meters

The centre of the tower; above the ground = 2b = 2(4) = 8 meters

Thus, the diameter at the centre of the tower is 4 meters and the centre of the tower is 8 meters above the ground.

Learn more about the hyperbola here:

brainly.com/question/12919612

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Answer:

40, 80

Step-by-step explanation: