The correct answer is option B which is u = ( x³ + 1).
The polynomial having a degree of two or the maximum power of the variable in a polynomial will be 2 is defined as the quadratic equation and it will cut two intercepts on the graph at the x-axis.
Given expression is as follows:-
16(x³ + 1)² − 22(x³ + 1) − 3 = 0
Put u = ( x³ + 1) the equation will become:-
16u² -22u-3 = 0
Now the above equation has become a quadratic equation.
Therefore the correct answer is option B which is u = ( x³ + 1).
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