Respuesta :

  • y=√4x+9+2
  • y=√4x+11

As it's a square root the underroot value must be greater than or equal to 0

So

let's find out the domain

  • √4x+11≥0
  • 4x+11≥0
  • 4x≥-11
  • x≥-11/4

Domain

  • [-11/4,oo)

Answer:

[-11/4, ∞)

Step-by-step explanation:

Given :

y = √(4x + 9 + 2)

Simplifying :

y = √(4x + 11)

Now, the term in the bracket has to be greater than or equal to 0 to be real.

Hence,

⇒ 4x + 11 ≥ 0

⇒ 4x ≥ -11

⇒ x ≥ -11/4 [Lower limit]

Infinity will be the upper limit as the numbers increase indefinitely.

The domain will be :

[-11/4, ∞)