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A sample of helium gas has a volume of 6.50l at a pressure of 845 mmhg and a temperature of 25oc. what is the pressure of the gas in atm when the volume and temperature of the gas sample are changed to 1850 ml and 325 k

Respuesta :

Answer:

4.25atm

Explanation:

[tex]\frac{P1V1}{T1}\\[/tex]=[tex]\frac{P2V2}{T2}[/tex]

where ,

p1 =845/760=1.11atm

v1=6.50l

t1=25c +273k=298k

p2=?

v2=1850/1000=1.85l

t2=325k

so answer is 4.25 atm