Which is the equation of the line passing through (0,4) and (8,0)?

Answer:
[tex]\sf y = -\dfrac{1}{2} x +4[/tex]
Find slope (m):
[tex]\sf slope: \dfrac{y_2 - y_1}{x_2- x_1} \ \ where \ (x_1 , \ y_1), ( x_2 , \ y_2) \ are \ points[/tex]
[tex]\rightarrow \sf slope \ (m): \dfrac{0-4}{4-0} = -\dfrac{1}{2}[/tex]
Now, find equation:
[tex]\sf y -y_1 = m(x - x_1) \ \ \ \ \textsc where \ (x_1, y_1 ) \ are \ points[/tex]
[tex]\rightarrow \sf y - 4 = -\dfrac{1}{2} (x - 0)[/tex]
[tex]\rightarrow \sf y = -\dfrac{1}{2} x +4[/tex]