Using a trigonometric identity, it is found that the values of the cosine and the tangent of the angle are given by:
- [tex]\cos{\theta} = \pm \frac{2\sqrt{2}}{3}[/tex]
- [tex]\tan{\theta} = \pm \frac{\sqrt{2}}{4}[/tex]
What is the trigonometric identity using in this problem?
The identity that relates the sine squared and the cosine squared of the angle, as follows:
[tex]\sin^{2}{\theta} + \cos^{2}{\theta} = 1[/tex]
In this problem, we have that the sine is given by:
[tex]\sin{\theta} = \frac{1}{3}[/tex]
Hence, applying the identity, the cosine is given as follows:
[tex]\cos^2{\theta} = 1 - \sin^2{\theta}[/tex]
[tex]\cos^2{\theta} = 1 - \left(\frac{1}{3}\right)^2[/tex]
[tex]\cos^2{\theta} = 1 - \frac{1}{9}[/tex]
[tex]\cos^2{\theta} = \frac{8}{9}[/tex]
[tex]\cos{\theta} = \pm \sqrt{\frac{8}{9}}[/tex]
[tex]\cos{\theta} = \pm \frac{2\sqrt{2}}{3}[/tex]
The tangent is given by the sine divided by the cosine, hence:
[tex]\tan{\theta} = \frac{\sin{\theta}}{\cos{\theta}}[/tex]
[tex]\tan{\theta} = \frac{\frac{1}{3}}{\pm \frac{2\sqrt{2}}{3}}[/tex]
[tex]\tan{\theta} = \pm \frac{1}{2\sqrt{2}} \times \frac{\sqrt{2}}{\sqrt{2}}[/tex]
[tex]\tan{\theta} = \pm \frac{\sqrt{2}}{4}[/tex]
More can be learned about trigonometric identities at https://brainly.com/question/24496175
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