An automobile manufacturer produces production parts with 98% accuracy. What is the probability that in a production run of 25 parts, at most 2 are found to be defective?

Respuesta :

An automobile manufacturer produces production parts with 98% accuracy.  the probability is mathematically given as

P(X\leq2) = 0.9868

What is the probability that in a production run of 25 parts, at most 2 are found to be defective?

Generally, the equation for the probability is mathematically given as

[tex]P(X\leq2) = P(X=0) + P(X=1) + P(X=2)[/tex]

Therefore

[tex]P(X=0)=\binom{25}{0}* 0.98^{25}* 0.02^{0}=1* 0.6035* 1\\\\P(X=0)=0.6035[/tex]

Hence

P(X=1)=0.3079

P(X=0)=0.07554

In conclusion, bringing the equation into view

 [tex]P(X\leq2) = P(X=0) + P(X=1) + P(X=2)[/tex]

[tex]P(X\leq2) = 0.6035 +0.3079 + 0.07554[/tex]

P(X\leq2) = 0.9868

Read more about probability

https://brainly.com/question/795909

#SPJ1