What is the equation,
in slope-intercept form, of the line that is perpendicular to the line
y- 4 = -(x-6) and passes through the point (-2,-2)?
O y=-x-10
Oy=-3x+10
O y=x-1
O y = x + 1

Respuesta :

The equation, in slope-intercept form, of the line that is perpendicular to the line y- 4 = -(x-6) and passes through the point (-2,-2) is y = x.

How to represent equation in slope intercept form?

The equation in slope intercept form is represented as follows;

y = mx + b

where

  • m = slope
  • b = y-intercept

Therefore,

perpendicular lines follows the rule as follows;

m₁m₂ = -1

Therefore,

y - 4 = -(x - 6)

y - 4 = -x + 6

y = -x + 6 + 4

y = -x + 10

Therefore,

-1m₂ = -1

m₂ = 1

Hence, the line passes through (-2, -2).

Therefore,

-2 = 1(-2) + b

b = -2 + 2

b = 0

Therefore, the equation is as follows;

y = x

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