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Use the standard enthalpies of formation for the reactants and products to solve for the ΔHrxn for the following reaction. (The ΔHf of Hg2Cl2 is -265.2 kJ/mol and HgCl2 is -224.3 kJ/mol.)

Hg2Cl2 (s) HgCl2 (s) + Hg(l)

ΔHrxn =

The reaction is
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Respuesta :

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The enthalpy change of the reaction can be obtained from the enthalpies of formation as 40.9  kJ/mol .

What is enthalpy?

The term enthalpy is the heat absorbed or gained in a reaction. It is possible to obtain the enthalpy change of a reaction using the enthalpies of formation of reactants and products.

For the reaction; Hg2Cl2 (s) ------>HgCl2 (s) + Hg(l), we can find the enthalpy change of the reaction from;

ΔHrxn = ΔHfproducts - ΔHfreactants

ΔHrxn =  -224.3 kJ/mol - ( -265.2 kJ/mol )

ΔHrxn = 40.9  kJ/mol

Learn more about enthalpy:https://brainly.com/question/13996238

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