Will give brainliest!!! calculate the molarity (m) of sucrose, c12h22o11 (molecular weight 342 g/mol) in a solution of 105 g of solute in 0.5 l of solution. (answer with 2 decimal places)

Respuesta :

Answer:

0.61 M

Explanation:

The equation used to find molarity is:

Molarity (M or mol/L) = moles / volume (L)

To find the molarity of sucrose, you need to (1) convert grams C₁₂H₂₂O₁₁ to moles (via molecular weight) and then (2) use the molarity equation.

Step 1:

105 g C₁₂H₂₂O₁₁          1 mole
-----------------------  x  -----------------  = 0.307 moles C₁₂H₂₂O₁₁
                                    342 g

Step 2:

Molarity = moles / volume

Molarity = 0.307 moles / 0.5 L

Molarity = 0.61 M