A computer originally purchased for $2000, loses value according to the exponential equation

(Equation attached)

where:

V is the value in dollars of the computer
t is the time in years after the original purchase
h represents the time (in years) it takes for the value to reduce by one half
After 1 year, the computer has a value of approximately $1516.

a) What is the half-life of the value of the computer?

b) How long will it take for the computer to be worth 10% of its purchase price?

A computer originally purchased for 2000 loses value according to the exponential equation Equation attached where V is the value in dollars of the computer t i class=

Respuesta :

The half life of the value of the computer is =  2 years

The time it will take for the computer to be worth 10% of its purchase price= 3.5 years.

Calculation of the half-life of computer

V = value of computer= $2000

t = time after original purchase = 1 year

h = half-life of the value of the computer

The half-life value can be calculated using the given formula;

V(t) = 2000(1/2)^t/h

2000×1 = (2000×1/2)^1/h

2000= 1000^1/h

Make h the subject formula,

h= 2000/1000

h = 2 years

The time it will take for the computer to become 10% of its purchase price is,

10/100×2000

= 20000/100

=$200

If after 1 year the computer= $1516

This means that in a year the price of the computer reduces by approximately $500

Therefore it will take approximately 3.5 years to purchase the computer at 10% it's organic price.

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