In the equation (x-4)² + (y-0)² = 22 the centre is on the x-axis and the centre of a circle is (4, 0) option (B) is correct.
It is described as a set of points, where each point is at the same distance from a fixed point (called the centre of a circle)
We have given circles equation in the options.
We know the standard form of a circle is:
(x - h)² + (y - k)² = r²
In the above equation (h, k) is the centre of the circle and r is the radius.
If the circles have their centres on the x-axis then,
k = 0
The centre becomes: (h, 0)
In the equation (x-4)² + (y-0)² = 22 the value of k is zero.
And the centre of a circle is (4, 0)
Thus, in the equation (x-4)² + (y-0)² = 22 the centre is on the x-axis and the centre of a circle is (4, 0) option (B) is correct.
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