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PLEASEEEEEEEEEEEEEEEEEEEEEE Edgar rolls two six-sided number cubes. What is the probability that he rolls a 2 on
the first cube and a number less than 5 on the second cube? Use the diagram 1of

the sample space to help you.


a. 3/36=1/12

b. 2/36=1/18

c. 4/36=1/9

d. 7/36

PLEASEEEEEEEEEEEEEEEEEEEEEE Edgar rolls two sixsided number cubes What is the probability that he rolls a 2 on the first cube and a number less than 5 on the se class=

Respuesta :

Answer:  Choice C

4/36 = 1/9

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Explanation:

Circle the second row. This is where each of the red die results are "2"

Then look at the cases when the second die is less than "5". So we could have a 1, 2, 3, or 4 on this second die.

As you can see, there are 4 cases when the first number is a 2 (red) and the second number is less than 5 (white).

We have m = 4 cases we want out of n = 6*6 = 36 cases total.

m/n = 4/36 = 1/9 is our final answer.

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