A gas occupies 1.15 L at standard pressure and temperature and 1.56 L at 317 K and 650 mmHg, assuming ideal behavior.
An ideal gas is a gas whose behavior can be explained through ideal gas laws. One of them is the combined gas law.
A gas occupies 1.15 L (V₁) at STP (T₁ = 273,15 K and P₁ = 760 mmHg). We can calculate the temperature (T₂) at which V₂ = 1.56 L and P₂ = 650 mmHg, using the combined gas law.
[tex]\frac{P_1 \times V_1}{T_1} = \frac{P_2 \times V_2}{T_2}\\T_2 = \frac{P_2 \times V_2 \times T_1}{P_1 \times V_1} = \frac{650mmHg \times 1.56 L \times 273.15K}{760mmHg \times 1.15 L} = 317 K[/tex]
A gas occupies 1.15 L at standard pressure and temperature and 1.56 L at 317 K and 650 mmHg, assuming ideal behavior.
Learn more about ideal gases here: https://brainly.com/question/15634266
#SPJ1