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A ball is thrown from a height of 217 feet with an initial downward velocity of 17 fts. The ball's height h (in feet) after seconds is given by the following.
h = 217 - 17t-16t^2?

Respuesta :

MrRoyal

The maximum height of the ball is 221.52 feet

Missing part of the question

What is the maximum height of the ball?

How to determine the maximum height?

The equation of the function is given as:

h = 217 -17t - 16t^2

Differentiate the function

h' = - 17 - 32t

Set to 0

- 17 - 32t = 0

Add 17 to both sides

-32t = 17

Divide both sides by -32

t = -0.53125

Substitute t = -0.53125  in h = 217 -17t - 16t^2

h = 217 -17(-0.53125) - 16(-0.53125)^2

Evaluate

h = 221.515625

Approximate

h = 221.52

Hence, the maximum height of the ball is 221.52 feet

Read more about maximum values at:

https://brainly.com/question/10373132

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