1) A point charge (q1) has a magnitude of 3.0 x10-6 C. A second charge (q2) has a magnitude of -1.5 x10-6 C and is located 0.12 m from the first charge. Determine the electrostatic force each charge exerts on the other.

2) what will happen to the force in question 1 if the charge on q1 is doubled? Be specific in your answer - don't just say that it will increase or decrease - say how much it will increase by and give an explanation with your answer.

3) what will happen to the force in question 1 if the DISTANCE between q1 AND q2 is doubled?

The electrostatic force F between two charged objects placed distance apart is directly proportional to the product of the magnitude of charges and inversely proportional to the square of the distance between them.

F = kq₁q₂/d²

where coulomb constant, k = 9 x 10⁹ N.m²/C²

1) Given is a point charge (q1) has a magnitude of 3.0 x10⁻⁶ C. A second charge (q2) has a magnitude of -1.5 x10⁻⁶ C and is located 0.12 m from the first charge.

F = 9 x 10⁹x 3.0 x10⁻⁶x1.5 x10⁻⁶ / (0.12)²

F = 2.812 N

Thus, the electrostatic force each charge exerts on the other is 2.812 N.

2) When the charge q1 is doubled, new force will be

F' = 9 x 10⁹x (2 x3.0 x10⁻⁶)x1.5 x10⁻⁶ / (0.12)²

F = 2 x F

F' =2 x2.812 N

F' = 5.624 N

Thus, the electrostatic force if the charge on q1, doubled is 5.624 N.

3) If the distance between them is doubled without altering their charges, the force between them becomes

New force will be

F'' = 9 x 10⁹x 3.0 x10⁻⁶x1.5 x10⁻⁶ / (2 x 0.12)²

F'' = F/4

F'' =2.812 /4

F'' = 0.703 N

Thus, the electrostatic force if the distance between charges, doubled is 0.703 N

Learn more about electrostatic force.

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