The distance between the points A(-2, 3) and A'(2, 5) is 2√5 units if the point A(-2, 3) is translated using T: (x, y) → (x + 4, y + 2).
It is defined as the formula for finding the distance between two points. It has given the shortest path distance between two points.
The distance formula can be given as:
[tex]\rm d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
We have a point A(-2, 3)
After applying the translation:
T: (x,y) → (x + 4, y + 2)
A' = (-2+4, 3+2) = (2, 5)
The distance between A and A':
[tex]\rm d=\sqrt{(2+2)^2+(5-3)^2}[/tex]
d = √20
or
d = 2√5 units
Thus, the distance between the points A(-2, 3) and A'(2, 5) is 2√5 units if the point A(-2, 3) is translated using T: (x, y) → (x + 4, y + 2).
Learn more about the distance formula here:
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