Answer:
[tex](x,y) = \left(-\dfrac 12, 1 \right)[/tex]
Step-by-step explanation:
[tex]2x-y +2 = 0~~~~~...(i)\\\\4x-y+3=0~~~~~...(ii)\\\\\text{Now,}\\\\~~~~~~~\dfrac{x}{(-1)(3) - (-1)(2)} = \dfrac{y}{(2)(4) -2(3) } = \dfrac 1{2(-1) - (-1)(4)}\\\\\\\implies \dfrac{x}{-3+2} = \dfrac{y}{8-6} = \dfrac 1{-2+4}\\\\\\\implies -x = \dfrac y2 = \dfrac 12\\\\\\ \implies x = -\dfrac 12,~~~ y = 1[/tex]
