Answer:
Given function:
[tex]f(x)=\sqrt{x}[/tex]
Replace f(x) for y:
[tex]\implies y=\sqrt{x}[/tex]
Square both sides:
[tex]\implies y^2=x[/tex]
This is a sideways parabola that opens to the right, with an axis of symmetry at y = 0. (Refer to attachment 1)
If we square root this again, we get:
[tex]\implies \sqrt{y^2}=\sqrt{x}[/tex]
[tex]\implies y=\pm\sqrt{x}[/tex]
So [tex]y=\sqrt{x}[/tex] is the part of the parabola in quadrant I → (x, y)
And [tex]y=-\sqrt{x}[/tex] is the part of the parabola in quadrant IV → (x, -y)
(Refer to attachment 2)
Therefore, the graph of the given function is attachment 3.
