Respuesta :

The net magnetic field between the two parallel wires is determined as 1775 nT.

Magnetic field at wire 2 due to current 1

The magnetic field is calculated as follows;

[tex]B_z_1 = \frac{\mu _0 I_1}{2\pi r} \\\\B_z_1 = \frac{4\pi \times 10^{-7} \times 42 }{2\pi \times 7} \\\\B_z_1 = 1.2 \times 10^{-6} \ T[/tex]

Magnetic field at wire 1 due to current 2

The magnetic field is calculated as follows;

[tex]B_z_2= \frac{\mu _0 I_2}{2\pi r} \\\\B_z_2 = \frac{4\pi \times 10^{-7} \times 23 }{2\pi \times 8} \\\\B_z_2 = 5.75 \times 10^{-7} \ T[/tex]

Net magnetic field

B = BZ1 + BZ2

B = 1.2 x 10⁻⁶  + 5.75 x 10⁻⁷

B = 1.775 x 10⁻⁶ T

B = 1775 x 10⁻⁹ T

B = 1775 T nT

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