Help me with the following problem

The power dissipated in the 6 ohms resistor is determined as 24 W and the power dissipated in the 3 ohms resistor is determined as 48 W.
The power dissipated in the resistors is calculated as follows;
P = IV
where;
From Ohm's law, V = IR, ⇒ I = V/R
P = V²/R
where;
P = (12)²/6
P = 24 W
P = (12)²/3
P = 48 W
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