The discriminant of 0 = -2x^2 + 3 is 24 and it has 2 real solutions
The equation is given as:
0 = -2x^2 + 3
Rewrite as:
-2x^2 + 3 = 0
The discriminant of an equation is calculated using:
D = B^2 - 4AC
In this case, we have:
A = -2
B = 0
C = 3
So, we have:
D = (0)^2 - 4 * -2 * 3
Evaluate
D = 24
When the discriminant is 0 or more, then the equation has real roots
Hence, the discriminant of 0 = -2x^2 + 3 is 24 and it has 2 real solutions
Read more about quadratic functions at:
https://brainly.com/question/1214333
#SPJ1